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• الانـتـسـاب » Apr 2013
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• رقـم العـضـويـة » 111388
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• المشـــاركـات » 176
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• الـدولـة »
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• الـهـوايـة »
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• اسـم الـسـيـرفـر » No Server
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• الـجـنـس » Male
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• نقـاط التقييم » 10
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طلب مساعده
عندى مشكله كل ما اجى اضيف add Gift Scroll
عفوا ,,, لايمكنك مشاهده الروابط لانك غير مسجل لدينا [ للتسجيل اضغط هنا ]
كود PHP:
if(@JobID = '3118')---gift--- begin declare @tradenum int declare @gift varchar(128) set @gift =('ITEM_ETC_SD_TOKEN_01') SET @tradenum =(SELECT ABLECOUNT from _CharTrijobSafeTrade where CharID =@CharID ) if (@tradenum >=5) begin select @CharName16 =CharName16 from _Char where CharID=@CharID exec _ADD_ITEM_EXTERN @CharName16,@gift,200,1 update _CharTrijobSafeTrade set AbleCount =0 where CharID =@CharID end end

اكيد انا بعمل حاجه غلط لو ممكن حد يساعدنى ويضفهالى بى اى اسكرول
ده التابل : _AddTimedJob
كود PHP:
USE [SRO_VT_SHARD] GO /****** Object: StoredProcedure [dbo].[_AddTimedJob] Script Date: 05/11/2013 08:31:52 ص ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO
ALTER procedure [dbo].[_AddTimedJob] @CharID int, @Category tinyint, @JobID int, @TimeToKeep int, @Data1 int, @Data2 int, --##begin due to develop composite item @Data3 int, @Data4 int, @Data5 int, @Data6 int, @Data7 int, @Data8 int, @Serial64 bigint, @JID int --##end due to develop composite item as if (not exists (select CharID from _Char with (nolock) where CharID = @CharID)) return -1 if (@TimeToKeep <= 0) return -2 declare @NewJobID int set @NewJobID = 0
--##JobID 1 = Guild // JobID 2 = Thief/Hunter/Trader --##If you want to only have one not both, then just modify the line below! if (@JobID = 1 or @JobID = 2) BEGIN return -1 END ELSE BEGIN --##begin due to develop composite item insert into _TimedJob(CharID,Category,JobID,TimeToKeep,Data1,Data2,Data3,Data4,Data5,Data6,Data7,Data8,Serial64,JID) values(@CharID, @Category, @JobID, @TimeToKeep, @Data1, @Data2, @Data3, @Data4, @Data5, @Data6, @Data7, @Data8, @Serial64, @JID) END --##end due to develop composite item set @NewJobID = @@identity if (@@error <> 0 or @@rowcount = 0) return -3 return @NewJobID
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